3(x-3)=7x+19

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Solution for 3(x-3)=7x+19 equation: 



3(x-3)=7x+19

We move all terms to the left:

3(x-3)-(7x+19)=0

We multiply parentheses

3x-(7x+19)-9=0

We get rid of parentheses

3x-7x-19-9=0

We add all the numbers together, and all the variables

-4x-28=0

We move all terms containing x to the left, all other terms to the right

-4x=28

x=28/-4

x=-7

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