3(x-3)=7x-2(x+1)

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Solution for 3(x-3)=7x-2(x+1) equation: 



3(x-3)=7x-2(x+1)

We move all terms to the left:

3(x-3)-(7x-2(x+1))=0

We multiply parentheses

3x-(7x-2(x+1))-9=0



We calculate terms in parentheses: -(7x-2(x+1)), so:

7x-2(x+1)

We multiply parentheses

7x-2x-2

We add all the numbers together, and all the variables

5x-2

Back to the equation:

-(5x-2)



We get rid of parentheses

3x-5x+2-9=0

We add all the numbers together, and all the variables

-2x-7=0

We move all terms containing x to the left, all other terms to the right

-2x=7

x=7/-2

x=-3+1/2

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