3(x-3)=x+1-6(-2x-1)

Solution for 3(x-3)=x+1-6(-2x-1) equation:

3(x-3)=x+1-6(-2x-1)

We move all terms to the left:

3(x-3)-(x+1-6(-2x-1))=0

We multiply parentheses

3x-(x+1-6(-2x-1))-9=0


We calculate terms in parentheses: -(x+1-6(-2x-1)), so:

x+1-6(-2x-1)

determiningTheFunctionDomain
x-6(-2x-1)+1

We multiply parentheses

x+12x+6+1

We add all the numbers together, and all the variables

13x+7

Back to the equation:

-(13x+7)


We get rid of parentheses

3x-13x-7-9=0

We add all the numbers together, and all the variables

-10x-16=0

We move all terms containing x to the left, all other terms to the right

-10x=16

x=16/-10

x=-1+3/5