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3(x-3)=x-(2-3x)
We move all terms to the left:
3(x-3)-(x-(2-3x))=0
We add all the numbers together, and all the variables
3(x-3)-(x-(-3x+2))=0
We multiply parentheses
3x-(x-(-3x+2))-9=0
We calculate terms in parentheses: -(x-(-3x+2)), so:We get rid of parentheses
x-(-3x+2)
We get rid of parentheses
x+3x-2
We add all the numbers together, and all the variables
4x-2
Back to the equation:
-(4x-2)
3x-4x+2-9=0
We add all the numbers together, and all the variables
-1x-7=0
We move all terms containing x to the left, all other terms to the right
-x=7
x=7/-1
x=-7
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