3(x-35)-7(x+25)=30-9(x-5)

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Solution for 3(x-35)-7(x+25)=30-9(x-5) equation: 



3(x-35)-7(x+25)=30-9(x-5)

We move all terms to the left:

3(x-35)-7(x+25)-(30-9(x-5))=0

We multiply parentheses

3x-7x-(30-9(x-5))-105-175=0



We calculate terms in parentheses: -(30-9(x-5)), so:

30-9(x-5)

determiningTheFunctionDomain
-9(x-5)+30

We multiply parentheses

-9x+45+30

We add all the numbers together, and all the variables

-9x+75

Back to the equation:

-(-9x+75)



We add all the numbers together, and all the variables

-4x-(-9x+75)-280=0

We get rid of parentheses

-4x+9x-75-280=0

We add all the numbers together, and all the variables

5x-355=0

We move all terms containing x to the left, all other terms to the right

5x=355

x=355/5

x=71

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