3(x-4)(x+4)=0

Solution for 3(x-4)(x+4)=0 equation:

Simplifying
3(x + -4)(x + 4) = 0

Reorder the terms:
3(-4 + x)(x + 4) = 0

Reorder the terms:
3(-4 + x)(4 + x) = 0

Multiply (-4 + x) * (4 + x)
3(-4(4 + x) + x(4 + x)) = 0
3((4 * -4 + x * -4) + x(4 + x)) = 0
3((-16 + -4x) + x(4 + x)) = 0
3(-16 + -4x + (4 * x + x * x)) = 0
3(-16 + -4x + (4x + x2)) = 0

Combine like terms: -4x + 4x = 0
3(-16 + 0 + x2) = 0
3(-16 + x2) = 0
(-16 * 3 + x2 * 3) = 0
(-48 + 3x2) = 0

Solving
-48 + 3x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '48' to each side of the equation.
-48 + 48 + 3x2 = 0 + 48

Combine like terms: -48 + 48 = 0
0 + 3x2 = 0 + 48
3x2 = 0 + 48

Combine like terms: 0 + 48 = 48
3x2 = 48

Divide each side by '3'.
x2 = 16

Simplifying
x2 = 16

Take the square root of each side:
x = {-4, 4}