3(x-4)+10=22-2(2x+5)

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Solution for 3(x-4)+10=22-2(2x+5) equation: 



3(x-4)+10=22-2(2x+5)

We move all terms to the left:

3(x-4)+10-(22-2(2x+5))=0

We multiply parentheses

3x-(22-2(2x+5))-12+10=0



We calculate terms in parentheses: -(22-2(2x+5)), so:

22-2(2x+5)

determiningTheFunctionDomain
-2(2x+5)+22

We multiply parentheses

-4x-10+22

We add all the numbers together, and all the variables

-4x+12

Back to the equation:

-(-4x+12)



We add all the numbers together, and all the variables

3x-(-4x+12)-2=0

We get rid of parentheses

3x+4x-12-2=0

We add all the numbers together, and all the variables

7x-14=0

We move all terms containing x to the left, all other terms to the right

7x=14

x=14/7

x=2

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