3(x-4)+12=42

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Solution for 3(x-4)+12=42 equation: 



3(x-4)+12=42

We move all terms to the left:

3(x-4)+12-(42)=0

We add all the numbers together, and all the variables

3(x-4)-30=0

We multiply parentheses

3x-12-30=0

We add all the numbers together, and all the variables

3x-42=0

We move all terms containing x to the left, all other terms to the right

3x=42

x=42/3

x=14

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