3(x-4)+15=5(x+2)-(x+1)

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Solution for 3(x-4)+15=5(x+2)-(x+1) equation: 



3(x-4)+15=5(x+2)-(x+1)

We move all terms to the left:

3(x-4)+15-(5(x+2)-(x+1))=0

We multiply parentheses

3x-(5(x+2)-(x+1))-12+15=0



We calculate terms in parentheses: -(5(x+2)-(x+1)), so:

5(x+2)-(x+1)

We multiply parentheses

5x-(x+1)+10

We get rid of parentheses

5x-x-1+10

We add all the numbers together, and all the variables

4x+9

Back to the equation:

-(4x+9)



We add all the numbers together, and all the variables

3x-(4x+9)+3=0

We get rid of parentheses

3x-4x-9+3=0

We add all the numbers together, and all the variables

-1x-6=0

We move all terms containing x to the left, all other terms to the right

-x=6

x=6/-1

x=-6

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