3(x-4)+18=12

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Solution for 3(x-4)+18=12 equation: 



3(x-4)+18=12

We move all terms to the left:

3(x-4)+18-(12)=0

We add all the numbers together, and all the variables

3(x-4)+6=0

We multiply parentheses

3x-12+6=0

We add all the numbers together, and all the variables

3x-6=0

We move all terms containing x to the left, all other terms to the right

3x=6

x=6/3

x=2

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