3(x-4)+2(x-2)=6(x-1)

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Solution for 3(x-4)+2(x-2)=6(x-1) equation: 



3(x-4)+2(x-2)=6(x-1)

We move all terms to the left:

3(x-4)+2(x-2)-(6(x-1))=0

We multiply parentheses

3x+2x-(6(x-1))-12-4=0



We calculate terms in parentheses: -(6(x-1)), so:

6(x-1)

We multiply parentheses

6x-6

Back to the equation:

-(6x-6)



We add all the numbers together, and all the variables

5x-(6x-6)-16=0

We get rid of parentheses

5x-6x+6-16=0

We add all the numbers together, and all the variables

-1x-10=0

We move all terms containing x to the left, all other terms to the right

-x=10

x=10/-1

x=-10

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