3(x-4)+2=2(-x+1)

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Solution for 3(x-4)+2=2(-x+1) equation: 



3(x-4)+2=2(-x+1)

We move all terms to the left:

3(x-4)+2-(2(-x+1))=0

We add all the numbers together, and all the variables

3(x-4)-(2(-1x+1))+2=0

We multiply parentheses

3x-(2(-1x+1))-12+2=0



We calculate terms in parentheses: -(2(-1x+1)), so:

2(-1x+1)

We multiply parentheses

-2x+2

Back to the equation:

-(-2x+2)



We add all the numbers together, and all the variables

3x-(-2x+2)-10=0

We get rid of parentheses

3x+2x-2-10=0

We add all the numbers together, and all the variables

5x-12=0

We move all terms containing x to the left, all other terms to the right

5x=12

x=12/5

x=2+2/5

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