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3(x-4)+2=3(x-1)
We move all terms to the left:
3(x-4)+2-(3(x-1))=0
We multiply parentheses
3x-(3(x-1))-12+2=0
We calculate terms in parentheses: -(3(x-1)), so:We add all the numbers together, and all the variables
3(x-1)
We multiply parentheses
3x-3
Back to the equation:
-(3x-3)
3x-(3x-3)-10=0
We get rid of parentheses
3x-3x+3-10=0
We add all the numbers together, and all the variables
-7!=0
There is no solution for this equation
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