3(x-4)+2=4(x-1)+7

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Solution for 3(x-4)+2=4(x-1)+7 equation: 



3(x-4)+2=4(x-1)+7

We move all terms to the left:

3(x-4)+2-(4(x-1)+7)=0

We multiply parentheses

3x-(4(x-1)+7)-12+2=0



We calculate terms in parentheses: -(4(x-1)+7), so:

4(x-1)+7

We multiply parentheses

4x-4+7

We add all the numbers together, and all the variables

4x+3

Back to the equation:

-(4x+3)



We add all the numbers together, and all the variables

3x-(4x+3)-10=0

We get rid of parentheses

3x-4x-3-10=0

We add all the numbers together, and all the variables

-1x-13=0

We move all terms containing x to the left, all other terms to the right

-x=13

x=13/-1

x=-13

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