3(x-4)+2=7(x+3)-6

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Solution for 3(x-4)+2=7(x+3)-6 equation: 



3(x-4)+2=7(x+3)-6

We move all terms to the left:

3(x-4)+2-(7(x+3)-6)=0

We multiply parentheses

3x-(7(x+3)-6)-12+2=0



We calculate terms in parentheses: -(7(x+3)-6), so:

7(x+3)-6

We multiply parentheses

7x+21-6

We add all the numbers together, and all the variables

7x+15

Back to the equation:

-(7x+15)



We add all the numbers together, and all the variables

3x-(7x+15)-10=0

We get rid of parentheses

3x-7x-15-10=0

We add all the numbers together, and all the variables

-4x-25=0

We move all terms containing x to the left, all other terms to the right

-4x=25

x=25/-4

x=-6+1/4

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