3(x-4)+2x+7=4(x-5)

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Solution for 3(x-4)+2x+7=4(x-5) equation: 



3(x-4)+2x+7=4(x-5)

We move all terms to the left:

3(x-4)+2x+7-(4(x-5))=0

We add all the numbers together, and all the variables

2x+3(x-4)-(4(x-5))+7=0

We multiply parentheses

2x+3x-(4(x-5))-12+7=0



We calculate terms in parentheses: -(4(x-5)), so:

4(x-5)

We multiply parentheses

4x-20

Back to the equation:

-(4x-20)



We add all the numbers together, and all the variables

5x-(4x-20)-5=0

We get rid of parentheses

5x-4x+20-5=0

We add all the numbers together, and all the variables

x+15=0

We move all terms containing x to the left, all other terms to the right

x=-15

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