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3(x-4)+2x=5(x+3)-28
We move all terms to the left:
3(x-4)+2x-(5(x+3)-28)=0
We add all the numbers together, and all the variables
2x+3(x-4)-(5(x+3)-28)=0
We multiply parentheses
2x+3x-(5(x+3)-28)-12=0
We calculate terms in parentheses: -(5(x+3)-28), so:We add all the numbers together, and all the variables
5(x+3)-28
We multiply parentheses
5x+15-28
We add all the numbers together, and all the variables
5x-13
Back to the equation:
-(5x-13)
5x-(5x-13)-12=0
We get rid of parentheses
5x-5x+13-12=0
We add all the numbers together, and all the variables
1!=0
There is no solution for this equation
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