3(x-4)+3(x-4)+x+6+x+6=720

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Solution for 3(x-4)+3(x-4)+x+6+x+6=720 equation: 



3(x-4)+3(x-4)+x+6+x+6=720

We move all terms to the left:

3(x-4)+3(x-4)+x+6+x+6-(720)=0

We add all the numbers together, and all the variables

2x+3(x-4)+3(x-4)-708=0

We multiply parentheses

2x+3x+3x-12-12-708=0

We add all the numbers together, and all the variables

8x-732=0

We move all terms containing x to the left, all other terms to the right

8x=732

x=732/8

x=91+1/2

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