3(x-4)+3x=6(2x+1)

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Solution for 3(x-4)+3x=6(2x+1) equation: 



3(x-4)+3x=6(2x+1)

We move all terms to the left:

3(x-4)+3x-(6(2x+1))=0

We add all the numbers together, and all the variables

3x+3(x-4)-(6(2x+1))=0

We multiply parentheses

3x+3x-(6(2x+1))-12=0



We calculate terms in parentheses: -(6(2x+1)), so:

6(2x+1)

We multiply parentheses

12x+6

Back to the equation:

-(12x+6)



We add all the numbers together, and all the variables

6x-(12x+6)-12=0

We get rid of parentheses

6x-12x-6-12=0

We add all the numbers together, and all the variables

-6x-18=0

We move all terms containing x to the left, all other terms to the right

-6x=18

x=18/-6

x=-3

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