3(x-4)+4(4x+5)=34

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Solution for 3(x-4)+4(4x+5)=34 equation: 



3(x-4)+4(4x+5)=34

We move all terms to the left:

3(x-4)+4(4x+5)-(34)=0

We multiply parentheses

3x+16x-12+20-34=0

We add all the numbers together, and all the variables

19x-26=0

We move all terms containing x to the left, all other terms to the right

19x=26

x=26/19

x=1+7/19

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