3(x-4)+4(x+1)=13

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Solution for 3(x-4)+4(x+1)=13 equation:


Simplifying
3(x + -4) + 4(x + 1) = 13

Reorder the terms:
3(-4 + x) + 4(x + 1) = 13
(-4 * 3 + x * 3) + 4(x + 1) = 13
(-12 + 3x) + 4(x + 1) = 13

Reorder the terms:
-12 + 3x + 4(1 + x) = 13
-12 + 3x + (1 * 4 + x * 4) = 13
-12 + 3x + (4 + 4x) = 13

Reorder the terms:
-12 + 4 + 3x + 4x = 13

Combine like terms: -12 + 4 = -8
-8 + 3x + 4x = 13

Combine like terms: 3x + 4x = 7x
-8 + 7x = 13

Solving
-8 + 7x = 13

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 8 + 7x = 13 + 8

Combine like terms: -8 + 8 = 0
0 + 7x = 13 + 8
7x = 13 + 8

Combine like terms: 13 + 8 = 21
7x = 21

Divide each side by '7'.
x = 3

Simplifying
x = 3

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