3(x-4)+5(x-2)=2(x-6)-4(5-x)

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Solution for 3(x-4)+5(x-2)=2(x-6)-4(5-x) equation: 



3(x-4)+5(x-2)=2(x-6)-4(5-x)

We move all terms to the left:

3(x-4)+5(x-2)-(2(x-6)-4(5-x))=0

We add all the numbers together, and all the variables

3(x-4)+5(x-2)-(2(x-6)-4(-1x+5))=0

We multiply parentheses

3x+5x-(2(x-6)-4(-1x+5))-12-10=0



We calculate terms in parentheses: -(2(x-6)-4(-1x+5)), so:

2(x-6)-4(-1x+5)

We multiply parentheses

2x+4x-12-20

We add all the numbers together, and all the variables

6x-32

Back to the equation:

-(6x-32)



We add all the numbers together, and all the variables

8x-(6x-32)-22=0

We get rid of parentheses

8x-6x+32-22=0

We add all the numbers together, and all the variables

2x+10=0

We move all terms containing x to the left, all other terms to the right

2x=-10

x=-10/2

x=-5

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