3(x-4)+5(x-2)=20

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Solution for 3(x-4)+5(x-2)=20 equation: 



3(x-4)+5(x-2)=20

We move all terms to the left:

3(x-4)+5(x-2)-(20)=0

We multiply parentheses

3x+5x-12-10-20=0

We add all the numbers together, and all the variables

8x-42=0

We move all terms containing x to the left, all other terms to the right

8x=42

x=42/8

x=5+1/4

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