3(x-4)+5=7x+13

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Solution for 3(x-4)+5=7x+13 equation: 



3(x-4)+5=7x+13

We move all terms to the left:

3(x-4)+5-(7x+13)=0

We multiply parentheses

3x-(7x+13)-12+5=0

We get rid of parentheses

3x-7x-13-12+5=0

We add all the numbers together, and all the variables

-4x-20=0

We move all terms containing x to the left, all other terms to the right

-4x=20

x=20/-4

x=-5

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