3(x-4)+6=(x-1)+1

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Solution for 3(x-4)+6=(x-1)+1 equation: 



3(x-4)+6=(x-1)+1

We move all terms to the left:

3(x-4)+6-((x-1)+1)=0

We multiply parentheses

3x-((x-1)+1)-12+6=0



We calculate terms in parentheses: -((x-1)+1), so:

(x-1)+1

We get rid of parentheses

x-1+1

We add all the numbers together, and all the variables

x

Back to the equation:

-(x)



We add all the numbers together, and all the variables

2x-6=0

We move all terms containing x to the left, all other terms to the right

2x=6

x=6/2

x=3

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