3(x-4)+6=2(3x+6)

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Solution for 3(x-4)+6=2(3x+6) equation: 



3(x-4)+6=2(3x+6)

We move all terms to the left:

3(x-4)+6-(2(3x+6))=0

We multiply parentheses

3x-(2(3x+6))-12+6=0



We calculate terms in parentheses: -(2(3x+6)), so:

2(3x+6)

We multiply parentheses

6x+12

Back to the equation:

-(6x+12)



We add all the numbers together, and all the variables

3x-(6x+12)-6=0

We get rid of parentheses

3x-6x-12-6=0

We add all the numbers together, and all the variables

-3x-18=0

We move all terms containing x to the left, all other terms to the right

-3x=18

x=18/-3

x=-6

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