3(x-4)+6=5(x-1)+13

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Solution for 3(x-4)+6=5(x-1)+13 equation: 



3(x-4)+6=5(x-1)+13

We move all terms to the left:

3(x-4)+6-(5(x-1)+13)=0

We multiply parentheses

3x-(5(x-1)+13)-12+6=0



We calculate terms in parentheses: -(5(x-1)+13), so:

5(x-1)+13

We multiply parentheses

5x-5+13

We add all the numbers together, and all the variables

5x+8

Back to the equation:

-(5x+8)



We add all the numbers together, and all the variables

3x-(5x+8)-6=0

We get rid of parentheses

3x-5x-8-6=0

We add all the numbers together, and all the variables

-2x-14=0

We move all terms containing x to the left, all other terms to the right

-2x=14

x=14/-2

x=-7

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