3(x-4)+7(x+4)=2(x+4)(x-4)

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Solution for 3(x-4)+7(x+4)=2(x+4)(x-4) equation: 



3(x-4)+7(x+4)=2(x+4)(x-4)

We move all terms to the left:

3(x-4)+7(x+4)-(2(x+4)(x-4))=0

We use the square of the difference formula

x^2+3(x-4)+7(x+4)+16=0

We multiply parentheses

x^2+3x+7x-12+28+16=0

We add all the numbers together, and all the variables

x^2+10x+32=0

a = 1; b = 10; c = +32;
Δ = b2-4ac
Δ = 102-4·1·32
Δ = -28
Delta is less than zero, so there is no solution for the equation

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