3(x-4)+7=2(x+1)

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Solution for 3(x-4)+7=2(x+1) equation: 



3(x-4)+7=2(x+1)

We move all terms to the left:

3(x-4)+7-(2(x+1))=0

We multiply parentheses

3x-(2(x+1))-12+7=0



We calculate terms in parentheses: -(2(x+1)), so:

2(x+1)

We multiply parentheses

2x+2

Back to the equation:

-(2x+2)



We add all the numbers together, and all the variables

3x-(2x+2)-5=0

We get rid of parentheses

3x-2x-2-5=0

We add all the numbers together, and all the variables

x-7=0

We move all terms containing x to the left, all other terms to the right

x=7

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