3(x-4)+7x=3x-12+7x

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Solution for 3(x-4)+7x=3x-12+7x equation: 



3(x-4)+7x=3x-12+7x

We move all terms to the left:

3(x-4)+7x-(3x-12+7x)=0

We add all the numbers together, and all the variables

3(x-4)+7x-(10x-12)=0

We add all the numbers together, and all the variables

7x+3(x-4)-(10x-12)=0

We multiply parentheses

7x+3x-(10x-12)-12=0

We get rid of parentheses

7x+3x-10x+12-12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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