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3(x-4)+7x=3x-12+7x
We move all terms to the left:
3(x-4)+7x-(3x-12+7x)=0
We add all the numbers together, and all the variables
3(x-4)+7x-(10x-12)=0
We add all the numbers together, and all the variables
7x+3(x-4)-(10x-12)=0
We multiply parentheses
7x+3x-(10x-12)-12=0
We get rid of parentheses
7x+3x-10x+12-12=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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