3(x-4)+7x=4x+6(x-2)

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Solution for 3(x-4)+7x=4x+6(x-2) equation: 



3(x-4)+7x=4x+6(x-2)

We move all terms to the left:

3(x-4)+7x-(4x+6(x-2))=0

We add all the numbers together, and all the variables

7x+3(x-4)-(4x+6(x-2))=0

We multiply parentheses

7x+3x-(4x+6(x-2))-12=0



We calculate terms in parentheses: -(4x+6(x-2)), so:

4x+6(x-2)

We multiply parentheses

4x+6x-12

We add all the numbers together, and all the variables

10x-12

Back to the equation:

-(10x-12)



We add all the numbers together, and all the variables

10x-(10x-12)-12=0

We get rid of parentheses

10x-10x+12-12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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