3(x-4)+8=12+x

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Solution for 3(x-4)+8=12+x equation: 



3(x-4)+8=12+x

We move all terms to the left:

3(x-4)+8-(12+x)=0

We add all the numbers together, and all the variables

3(x-4)-(x+12)+8=0

We multiply parentheses

3x-(x+12)-12+8=0

We get rid of parentheses

3x-x-12-12+8=0

We add all the numbers together, and all the variables

2x-16=0

We move all terms containing x to the left, all other terms to the right

2x=16

x=16/2

x=8

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