3(x-4)+8x=7x+12

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Solution for 3(x-4)+8x=7x+12 equation: 



3(x-4)+8x=7x+12

We move all terms to the left:

3(x-4)+8x-(7x+12)=0

We add all the numbers together, and all the variables

8x+3(x-4)-(7x+12)=0

We multiply parentheses

8x+3x-(7x+12)-12=0

We get rid of parentheses

8x+3x-7x-12-12=0

We add all the numbers together, and all the variables

4x-24=0

We move all terms containing x to the left, all other terms to the right

4x=24

x=24/4

x=6

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