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3(x-4)+x=10x+10-7x-22
We move all terms to the left:
3(x-4)+x-(10x+10-7x-22)=0
We add all the numbers together, and all the variables
3(x-4)+x-(3x-12)=0
We add all the numbers together, and all the variables
x+3(x-4)-(3x-12)=0
We multiply parentheses
x+3x-(3x-12)-12=0
We get rid of parentheses
x+3x-3x+12-12=0
We add all the numbers together, and all the variables
x=0
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