3(x-4)+x=4(x-5)+8

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Solution for 3(x-4)+x=4(x-5)+8 equation: 


Simplifying
3(x + -4) + x = 4(x + -5) + 8

Reorder the terms:
3(-4 + x) + x = 4(x + -5) + 8
(-4 * 3 + x * 3) + x = 4(x + -5) + 8
(-12 + 3x) + x = 4(x + -5) + 8

Combine like terms: 3x + x = 4x
-12 + 4x = 4(x + -5) + 8

Reorder the terms:
-12 + 4x = 4(-5 + x) + 8
-12 + 4x = (-5 * 4 + x * 4) + 8
-12 + 4x = (-20 + 4x) + 8

Reorder the terms:
-12 + 4x = -20 + 8 + 4x

Combine like terms: -20 + 8 = -12
-12 + 4x = -12 + 4x

Add '12' to each side of the equation.
-12 + 12 + 4x = -12 + 12 + 4x

Combine like terms: -12 + 12 = 0
0 + 4x = -12 + 12 + 4x
4x = -12 + 12 + 4x

Combine like terms: -12 + 12 = 0
4x = 0 + 4x
4x = 4x

Add '-4x' to each side of the equation.
4x + -4x = 4x + -4x

Combine like terms: 4x + -4x = 0
0 = 4x + -4x

Combine like terms: 4x + -4x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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