3(x-4)+x=4x-12

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Solution for 3(x-4)+x=4x-12 equation: 



3(x-4)+x=4x-12

We move all terms to the left:

3(x-4)+x-(4x-12)=0

We add all the numbers together, and all the variables

x+3(x-4)-(4x-12)=0

We multiply parentheses

x+3x-(4x-12)-12=0

We get rid of parentheses

x+3x-4x+12-12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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