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3(x-4)-(5-2x)=5(2x-1)-27
We move all terms to the left:
3(x-4)-(5-2x)-(5(2x-1)-27)=0
We add all the numbers together, and all the variables
3(x-4)-(-2x+5)-(5(2x-1)-27)=0
We multiply parentheses
3x-(-2x+5)-(5(2x-1)-27)-12=0
We get rid of parentheses
3x+2x-(5(2x-1)-27)-5-12=0
We calculate terms in parentheses: -(5(2x-1)-27), so:We add all the numbers together, and all the variables
5(2x-1)-27
We multiply parentheses
10x-5-27
We add all the numbers together, and all the variables
10x-32
Back to the equation:
-(10x-32)
5x-(10x-32)-17=0
We get rid of parentheses
5x-10x+32-17=0
We add all the numbers together, and all the variables
-5x+15=0
We move all terms containing x to the left, all other terms to the right
-5x=-15
x=-15/-5
x=+3
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