3(x-4)-(x-2)=1

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Solution for 3(x-4)-(x-2)=1 equation:



3(x-4)-(x-2)=1
We move all terms to the left:
3(x-4)-(x-2)-(1)=0
We multiply parentheses
3x-(x-2)-12-1=0
We get rid of parentheses
3x-x+2-12-1=0
We add all the numbers together, and all the variables
2x-11=0
We move all terms containing x to the left, all other terms to the right
2x=11
x=11/2
x=5+1/2

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