3(x-4)-(x-5)=6x-2(x-5)

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Solution for 3(x-4)-(x-5)=6x-2(x-5) equation:



3(x-4)-(x-5)=6x-2(x-5)
We move all terms to the left:
3(x-4)-(x-5)-(6x-2(x-5))=0
We multiply parentheses
3x-(x-5)-(6x-2(x-5))-12=0
We get rid of parentheses
3x-x-(6x-2(x-5))+5-12=0
We calculate terms in parentheses: -(6x-2(x-5)), so:
6x-2(x-5)
We multiply parentheses
6x-2x+10
We add all the numbers together, and all the variables
4x+10
Back to the equation:
-(4x+10)
We add all the numbers together, and all the variables
2x-(4x+10)-7=0
We get rid of parentheses
2x-4x-10-7=0
We add all the numbers together, and all the variables
-2x-17=0
We move all terms containing x to the left, all other terms to the right
-2x=17
x=17/-2
x=-8+1/2

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