3(x-4)-12=2(x-6)+7G

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Solution for 3(x-4)-12=2(x-6)+7G equation: 



3(x-4)-12=2(x-6)+7

We move all terms to the left:

3(x-4)-12-(2(x-6)+7)=0

We multiply parentheses

3x-(2(x-6)+7)-12-12=0



We calculate terms in parentheses: -(2(x-6)+7), so:

2(x-6)+7

We multiply parentheses

2x-12+7

We add all the numbers together, and all the variables

2x-5

Back to the equation:

-(2x-5)



We add all the numbers together, and all the variables

3x-(2x-5)-24=0

We get rid of parentheses

3x-2x+5-24=0

We add all the numbers together, and all the variables

x-19=0

We move all terms containing x to the left, all other terms to the right

x=19

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