3(x-4)-12=25x+42

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Solution for 3(x-4)-12=25x+42 equation: 



3(x-4)-12=25x+42

We move all terms to the left:

3(x-4)-12-(25x+42)=0

We multiply parentheses

3x-(25x+42)-12-12=0

We get rid of parentheses

3x-25x-42-12-12=0

We add all the numbers together, and all the variables

-22x-66=0

We move all terms containing x to the left, all other terms to the right

-22x=66

x=66/-22

x=-3

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