3(x-4)-15=2(x-5)-10

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Solution for 3(x-4)-15=2(x-5)-10 equation: 



3(x-4)-15=2(x-5)-10

We move all terms to the left:

3(x-4)-15-(2(x-5)-10)=0

We multiply parentheses

3x-(2(x-5)-10)-12-15=0



We calculate terms in parentheses: -(2(x-5)-10), so:

2(x-5)-10

We multiply parentheses

2x-10-10

We add all the numbers together, and all the variables

2x-20

Back to the equation:

-(2x-20)



We add all the numbers together, and all the variables

3x-(2x-20)-27=0

We get rid of parentheses

3x-2x+20-27=0

We add all the numbers together, and all the variables

x-7=0

We move all terms containing x to the left, all other terms to the right

x=7

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