3(x-4)-16=2(x-8)+16

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Solution for 3(x-4)-16=2(x-8)+16 equation: 



3(x-4)-16=2(x-8)+16

We move all terms to the left:

3(x-4)-16-(2(x-8)+16)=0

We multiply parentheses

3x-(2(x-8)+16)-12-16=0



We calculate terms in parentheses: -(2(x-8)+16), so:

2(x-8)+16

We multiply parentheses

2x-16+16

We add all the numbers together, and all the variables

2x

Back to the equation:

-(2x)



We add all the numbers together, and all the variables

x-28=0

We move all terms containing x to the left, all other terms to the right

x=28

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