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3(x-4)-16=2(x-8)-7
We move all terms to the left:
3(x-4)-16-(2(x-8)-7)=0
We multiply parentheses
3x-(2(x-8)-7)-12-16=0
We calculate terms in parentheses: -(2(x-8)-7), so:We add all the numbers together, and all the variables
2(x-8)-7
We multiply parentheses
2x-16-7
We add all the numbers together, and all the variables
2x-23
Back to the equation:
-(2x-23)
3x-(2x-23)-28=0
We get rid of parentheses
3x-2x+23-28=0
We add all the numbers together, and all the variables
x-5=0
We move all terms containing x to the left, all other terms to the right
x=5
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