3(x-4)-2(3x+4)=2(3-x)+5x+4

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Solution for 3(x-4)-2(3x+4)=2(3-x)+5x+4 equation: 



3(x-4)-2(3x+4)=2(3-x)+5x+4

We move all terms to the left:

3(x-4)-2(3x+4)-(2(3-x)+5x+4)=0

We add all the numbers together, and all the variables

3(x-4)-2(3x+4)-(2(-1x+3)+5x+4)=0

We multiply parentheses

3x-6x-(2(-1x+3)+5x+4)-12-8=0



We calculate terms in parentheses: -(2(-1x+3)+5x+4), so:

2(-1x+3)+5x+4

We add all the numbers together, and all the variables

5x+2(-1x+3)+4

We multiply parentheses

5x-2x+6+4

We add all the numbers together, and all the variables

3x+10

Back to the equation:

-(3x+10)



We add all the numbers together, and all the variables

-3x-(3x+10)-20=0

We get rid of parentheses

-3x-3x-10-20=0

We add all the numbers together, and all the variables

-6x-30=0

We move all terms containing x to the left, all other terms to the right

-6x=30

x=30/-6

x=-5

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