3(x-4)-2(3x+4)=4(3x-x)+5x+4

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Solution for 3(x-4)-2(3x+4)=4(3x-x)+5x+4 equation: 



3(x-4)-2(3x+4)=4(3x-x)+5x+4

We move all terms to the left:

3(x-4)-2(3x+4)-(4(3x-x)+5x+4)=0

We add all the numbers together, and all the variables

3(x-4)-2(3x+4)-(4(+2x)+5x+4)=0

We multiply parentheses

3x-6x-(4(+2x)+5x+4)-12-8=0



We calculate terms in parentheses: -(4(+2x)+5x+4), so:

4(+2x)+5x+4

We add all the numbers together, and all the variables

5x+4(+2x)+4

We multiply parentheses

5x+8x+4

We add all the numbers together, and all the variables

13x+4

Back to the equation:

-(13x+4)



We add all the numbers together, and all the variables

-3x-(13x+4)-20=0

We get rid of parentheses

-3x-13x-4-20=0

We add all the numbers together, and all the variables

-16x-24=0

We move all terms containing x to the left, all other terms to the right

-16x=24

x=24/-16

x=-1+1/2

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