3(x-4)-2(x-3)=5(-x-3)+6

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Solution for 3(x-4)-2(x-3)=5(-x-3)+6 equation: 



3(x-4)-2(x-3)=5(-x-3)+6

We move all terms to the left:

3(x-4)-2(x-3)-(5(-x-3)+6)=0

We add all the numbers together, and all the variables

3(x-4)-2(x-3)-(5(-1x-3)+6)=0

We multiply parentheses

3x-2x-(5(-1x-3)+6)-12+6=0



We calculate terms in parentheses: -(5(-1x-3)+6), so:

5(-1x-3)+6

We multiply parentheses

-5x-15+6

We add all the numbers together, and all the variables

-5x-9

Back to the equation:

-(-5x-9)



We add all the numbers together, and all the variables

x-(-5x-9)-6=0

We get rid of parentheses

x+5x+9-6=0

We add all the numbers together, and all the variables

6x+3=0

We move all terms containing x to the left, all other terms to the right

6x=-3

x=-3/6

x=-1/2

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