3(x-4)-2(x-5)=-2(x+1)-3

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Solution for 3(x-4)-2(x-5)=-2(x+1)-3 equation: 



3(x-4)-2(x-5)=-2(x+1)-3

We move all terms to the left:

3(x-4)-2(x-5)-(-2(x+1)-3)=0

We multiply parentheses

3x-2x-(-2(x+1)-3)-12+10=0



We calculate terms in parentheses: -(-2(x+1)-3), so:

-2(x+1)-3

We multiply parentheses

-2x-2-3

We add all the numbers together, and all the variables

-2x-5

Back to the equation:

-(-2x-5)



We add all the numbers together, and all the variables

x-(-2x-5)-2=0

We get rid of parentheses

x+2x+5-2=0

We add all the numbers together, and all the variables

3x+3=0

We move all terms containing x to the left, all other terms to the right

3x=-3

x=-3/3

x=-1

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