3(x-4)-2(x-5)=6+2(x+1)+3x

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Solution for 3(x-4)-2(x-5)=6+2(x+1)+3x equation: 



3(x-4)-2(x-5)=6+2(x+1)+3x

We move all terms to the left:

3(x-4)-2(x-5)-(6+2(x+1)+3x)=0

We multiply parentheses

3x-2x-(6+2(x+1)+3x)-12+10=0



We calculate terms in parentheses: -(6+2(x+1)+3x), so:

6+2(x+1)+3x

determiningTheFunctionDomain
2(x+1)+3x+6

We add all the numbers together, and all the variables

3x+2(x+1)+6

We multiply parentheses

3x+2x+2+6

We add all the numbers together, and all the variables

5x+8

Back to the equation:

-(5x+8)



We add all the numbers together, and all the variables

x-(5x+8)-2=0

We get rid of parentheses

x-5x-8-2=0

We add all the numbers together, and all the variables

-4x-10=0

We move all terms containing x to the left, all other terms to the right

-4x=10

x=10/-4

x=-2+1/2

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