3(x-4)-2(x-5)=6+2(x-3)

Solution for 3(x-4)-2(x-5)=6+2(x-3) equation:

3(x-4)-2(x-5)=6+2(x-3)

We move all terms to the left:

3(x-4)-2(x-5)-(6+2(x-3))=0

We multiply parentheses

3x-2x-(6+2(x-3))-12+10=0


We calculate terms in parentheses: -(6+2(x-3)), so:

6+2(x-3)

determiningTheFunctionDomain
2(x-3)+6

We multiply parentheses

2x-6+6

We add all the numbers together, and all the variables

2x

Back to the equation:

-(2x)


We add all the numbers together, and all the variables

-1x-2=0

We move all terms containing x to the left, all other terms to the right

-x=2

x=2/-1

x=-2